7x-[1x-(2x+8)]=3x-2

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Solution for 7x-[1x-(2x+8)]=3x-2 equation:


Simplifying
7x + -1[1x + -1(2x + 8)] = 3x + -2

Reorder the terms:
7x + -1[1x + -1(8 + 2x)] = 3x + -2
7x + -1[1x + (8 * -1 + 2x * -1)] = 3x + -2
7x + -1[1x + (-8 + -2x)] = 3x + -2

Reorder the terms:
7x + -1[-8 + 1x + -2x] = 3x + -2

Combine like terms: 1x + -2x = -1x
7x + -1[-8 + -1x] = 3x + -2
7x + [-8 * -1 + -1x * -1] = 3x + -2
7x + [8 + 1x] = 3x + -2

Reorder the terms:
8 + 7x + 1x = 3x + -2

Combine like terms: 7x + 1x = 8x
8 + 8x = 3x + -2

Reorder the terms:
8 + 8x = -2 + 3x

Solving
8 + 8x = -2 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
8 + 8x + -3x = -2 + 3x + -3x

Combine like terms: 8x + -3x = 5x
8 + 5x = -2 + 3x + -3x

Combine like terms: 3x + -3x = 0
8 + 5x = -2 + 0
8 + 5x = -2

Add '-8' to each side of the equation.
8 + -8 + 5x = -2 + -8

Combine like terms: 8 + -8 = 0
0 + 5x = -2 + -8
5x = -2 + -8

Combine like terms: -2 + -8 = -10
5x = -10

Divide each side by '5'.
x = -2

Simplifying
x = -2

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